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# LeetCode: 2. Add Two Numbers

Andriy AndrunevchynMy first task on LeetCode

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

**Input:** (2 -> 4 -> 3) + (5 -> 6 -> 4)

**Output:** 7 -> 0 -> 8

package problems.algorithm.twonumbers; /* * You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes * contain a single digit. Add the two numbers and return it as a linked list. * * Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 */ public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { ListNode result = new ListNode(0); add(result, l1, l2); System.out.println(result); return result; } private void add(ListNode listNode, ListNode l1, ListNode l2) { int val1 = (l1 != null ? l1.val : 0); int val2 = (l2 != null ? l2.val : 0); int sum = listNode.val + val1 + val2; listNode.val = sum % 10; int fraction = sum / 10; if (fraction != 0) { listNode.next = new ListNode(fraction); } ListNode next1 = l1 != null ? l1.next : null; ListNode next2 = l2 != null ? l2.next : null; if (next1 != null || next2 != null) { listNode.next = new ListNode(fraction); add(listNode.next, next1, next2); } } public static void main(String[] args) { ListNode l1 = new ListNode(2); l1.next = new ListNode(4); l1.next.next = new ListNode(3); ListNode l2 = new ListNode(5); l2.next = new ListNode(6); l2.next.next = new ListNode(4); Solution solution = new Solution(); solution.addTwoNumbers(l1, l2); } }

and ListNode class

package problems.algorithm.twonumbers; public class ListNode { int val; ListNode next; ListNode(int x) { val = x; } @Override public String toString() { StringBuilder builder = new StringBuilder(); builder.append(val); if (next != null) { builder.append("->"); builder.append(next); } return builder.toString(); } }

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